NPTEL Problem Solving Through Programming In C Week 12 : Programming Assignment 1-5

 

Week 12 : Programming Assignment 1

Due on 2023-10-19, 23:59 IST

Write a program in C to find the factorial of a given number using pointers.

Your last recorded submission was on 2023-10-09, 13:25 IST

Select the Language for this assignment.      --                     C               

#include <stdio.h>

void findFact(int, long int*);

int main()

{

        long int fact; //factorial of the number

        int num1; 

        scanf("%d",&num1); //The number is taken from test data

         findFact(num1, &fact);

         printf("The Factorial of %d is : %ld\n",num1, fact);

         return 0;

        }

void findFact(int n, long int *f)

        {

        int i;

       *f =1;

       for(i=1;i<=n;i++)

       *f=*f*i;

       }

You may submit any number of times before the due date. The final submission will be considered for grading.

This assignment has Public Test cases. Please click on "Compile & Run" button to see the status of Public test cases. Assignment will be evaluated only after submitting using Submit button below. If you only save as or compile and run the Program , your assignment will not be graded and you will not see your score after the deadline.

   

Private Test cases used for Evaluation	Status
Test Case 1	Passed

Week 12 : Programming Assignment 2

Due on 2023-10-19, 23:59 IST

Write a C program to print the Record of the Student Merit wise. Here a structure variable is defined which contains student rollno, name and score.

Select the Language for this assignment.      --                     C               

#include<stdio.h>

struct student

{

int rollno;

char name[20];

int score;

};

void main()

{

struct student s[20];

int i, n;

scanf("%d" ,&n); //No. of Students taken from test data

// Roll no., Name and Score of n students are taken from test data

for(i=0;i<n;i++)

{

scanf("%d", &s[i].rollno);

scanf("%s", s[i].name);

scanf("%d", &s[i].score);

}

//Complete the program so that merit list is printed in descending order

struct student temp;

int j;

for(i=0;i<n-1;i++)

{

for(j=0;j<n-1;j++)

{

if(s[j].score<s[j+1].score)

{

temp=s[j];

s[j]=s[j+1];

s[j+1]=temp;

}

}

}

printf("The Merit List is :\n");

for(i=0;i<n;i++)

{

printf("%d", s[i].rollno);

printf("  %s", s[i].name);

printf("  %d\n", s[i].score);

}

}

You may submit any number of times before the due date. The final submission will be considered for grading.

This assignment has Public Test cases. Please click on "Compile & Run" button to see the status of Public test cases. Assignment will be evaluated only after submitting using Submit button below. If you only save as or compile and run the Program , your assignment will not be graded and you will not see your score after the deadline.

   

Compilation : Passed
Public Test Cases: 1 / 1 Passed

Note: These tests may not be considered while scoring. Know more.

Public Test Cases	Input	Expected Output	Actual Output	Status
Test Case 1	3 1 Santanu 700 2 Aparna 550 3 Vivek 900	The Merit List is :\n 3 Vivek 900\n 1 Santanu 700\n 2 Aparna 550	The Merit List is :\n 3 Vivek 900\n 1 Santanu 700\n 2 Aparna 550\n	Passed after ignoring Presentation Error

Week 12 : Programming Assignment 3

Due on 2023-10-19, 23:59 IST

Write a C program to store n elements using Dynamic Memory Allocation - calloc() and find the Largest element

Select the Language for this assignment.      --                     C               

#include <stdio.h>

#include <stdlib.h>

int main()

{

    int n; 

    float *element;

    scanf("%d", &n); //Total number of elements

    // Allocate the memory for 'n' number of elements. 

    //Then take the elements as input from test data

element = (float*) calloc(n, sizeof(float));

    if(element == NULL)

    {

        printf("Error!!! memory not allocated.");

        exit(0);

    }

    // Stores the number entered by the user.

    int i;

    for(i = 0; i < n; ++i)

    {

        scanf("%f", element + i);

    }

 // find the largest

    for(i = 1; i < n; ++i)

    {

       if(*element < *(element + i))

         *element = *(element + i);

    }

    printf("Largest element = %.2f", *element);

    return 0;

}

You may submit any number of times before the due date. The final submission will be considered for grading.

This assignment has Public Test cases. Please click on "Compile & Run" button to see the status of Public test cases. Assignment will be evaluated only after submitting using Submit button below. If you only save as or compile and run the Program , your assignment will not be graded and you will not see your score after the deadline.

   

Compilation : Passed
Public Test Cases: 1 / 1 Passed

Note: These tests may not be considered while scoring. Know more.

Public Test Cases	Input	Expected Output	Actual Output	Status
Test Case 1	5 200 300 500 100 400	Largest element = 500.00	Largest element = 500.00	Passed

Week 12 : Programming Assignment 4

Due on 2023-10-19, 23:59 IST

Write a C program to find the sum of two 1D integer arrays ‘A’  and ‘B’ of same size and store the result in another array ‘C’, where the size of the array and the elements of the array are taken as input.
In the Test case the input is given as follows

5

10

20

30

40

50

1

2

3

4

5

So the output will be displayed as

Result is

11

22

33

44

55

Write the program accordingly. Use dynamic memory allocation. 

Select the Language for this assignment.      --                     C               

#include<stdio.h>

#include<stdlib.h>

void main()

{

 int i,n;

//The number of elements in each array is taken from test case data 

 scanf("%d", &n);

int *a,*b,*c;

 a = (int *) malloc(n*sizeof(int));

 b = (int *) malloc(n*sizeof(int));

 c = (int *) malloc(n*sizeof(int));

// Input Elements of First List;

 for(i=0;i<n;i++)

 {

  scanf("%d",a+i);

 }

 //Input Elements of Second List;

 for(i=0;i<n;i++)

 {

  scanf("%d",b+i);

 }

 for(i=0;i<n;i++)

 {

  *(c+i) = *(a+i) + *(b+i);

 }

printf("Result is\n");

 for(i=0; i<n; i++)

 {

  printf("%d\n",*(c+i));

 }

}

You may submit any number of times before the due date. The final submission will be considered for grading.

This assignment has Public Test cases. Please click on "Compile & Run" button to see the status of Public test cases. Assignment will be evaluated only after submitting using Submit button below. If you only save as or compile and run the Program , your assignment will not be graded and you will not see your score after the deadline.

   

Compilation : Passed
Public Test Cases: 2 / 2 Passed

Note: These tests may not be considered while scoring. Know more.

Public Test Cases	Input	Expected Output	Actual Output	Status
Test Case 1	5 10 20 30 40 50 1 2 3 4 5	Result is\n 11\n 22\n 33\n 44\n 55	Result is\n 11\n 22\n 33\n 44\n 55\n	Passed after ignoring Presentation Error
Test Case 2	4 100 200 300 400 400 300 200 100	Result is\n 500\n 500\n 500\n 500	Result is\n 500\n 500\n 500\n 500\n	Passed after ignoring Presentation Error

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